cooperfamily200
cooperfamily200 cooperfamily200
  • 23-04-2018
  • Physics
contestada

A tow truck applies a 848 N to a car at a 32.5°angle, and pulls the car 48.7 m in 18.3s. How much power was the truck using to tow the car?

Respuesta :

11beehshahbaz 11beehshahbaz
  • 23-04-2018
Power is the ratio of work done and the time taken to do the work.

So,

Power = Work Done / Time

Work done is the dot product of force and distance.

So,

Work done = F.d = Fdcos(Ф)
where Ф is the angle between force and displacement. Using the values, we get:

Work done =  848 x 48.7 x cos(32.5) = 34830.04 Joules

So,

Power = 34830.04/18.3 = 1903.28 W

Thus, truck was using 1903.28 Watts to tow the car
Answer Link

Otras preguntas

28/29 and 30 please short explanation thanks
Choose the correct description of the graph of the inequality x-3 is less than or equal to 5
solve for x: ax - bx = c(x - d)
how does the type of crust at a convergent plate boundary affect the occurrence of subduction zones ?
Television commercials have an influence on children.
Using partial quotients
Sweet t has 2 orange picks for every 5 green if their are 21 picks in all how many picks are orange
What is 4 divided by 1,035 and explain the work
on friday the temperature was 82 f the temperature changed by -2 on saturday , and then it changed by 5 on sunday , what was the temperature on sunday , explain
I need to let my mother know that Mister Green is the new science teacher. error concerning capitalization error concerning abbreviations error involving numbe