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23-05-2020
Chemistry

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A 1.5L intraveneous (IV) solution contains 919 grams glucose (C6H12O6). What is the molarity of this solution?

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23-05-2020

Answer:

3.4 M

Explanation:

M = grams/molar mass = ans./volume(L)

M = 919/180 = ans./1.5

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