The surface area of the base is
A = (1/2)bh
A = (1/2)(3 in)(2.6 in) = 3.9 in²
The surface area of each of the 3 sides is
A = (1/2)bh
A = (1/2)(3 in)(6 in) = 9 in²
The total surface area is that of the base and 3 sides:
A = (3.9 in²) +3(9 in²) = 30.9 in²
The surface area of the paperweight is 30.9 in².
