we can use the combined gas law equation to find volume of gas
[tex] \frac{P1V1}{T1} = \frac{P2V2}{T2} [/tex]
P - pressure
V - volume
T - temperature
parameters at STP conditions are on the left side and parameters for the second instance are on the right side of the equation
standard temperature is 273 K and standard pressure is 10⁵ Pa
substituting the values in the equation
[tex] \frac{ 10^{5}Pa*3L }{273 K} = \frac{50000Pa*V}{450K} [/tex]
V = 9.89 L
new volume is 9.89 L
answer is B) 9.89 L
