suarezlaura12 suarezlaura12
  • 23-04-2018
  • Mathematics
contestada

What is an equation of a circle with center (5,0) that passes through the point (1,1)

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sqdancefan
sqdancefan sqdancefan
  • 23-04-2018
The equation of a circle with center (h, k) and radius r is
  (x -h)² +(y -k)² = r²

This will be true for the given point, allowing us to find r².
  (1 -5)² +(1 -0)² = r² = 17

The desired equation is ...
  (x -5)² +y² = 17
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Answer Link
Sophiasana
Sophiasana Sophiasana
  • 23-04-2018
(x-5)2+y2=17
(5,0)=(h,k)
(1,1) =(x,y)
r2=17
Answer Link

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