V1 = 200mL = 0.20L, T1 = 275 K, P1 = 92.1 kPa
[tex]P1 = \frac{1atm}{101.325kPa} \times \frac{92.1kPa}{1} \\ = 0.909 \: atm[/tex]
PV = nRT --> PV/T = nR
[tex] \frac{P1V1}{T1} = \frac{P2V2}{T2} \\ \frac{(0.909)(0.20)}{275} = \frac{(1)V2}{275} [/tex]
[tex]V2 = \frac{(0.909)(0.20)(275)}{275} \\ = 0.909 \times 0.20 = 0.182 L \\ = 182 \: mL[/tex]
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