Respuesta :

carlosego
1. You con solve the quadratic equation x^2+20x+100=50 by following the proccedure below:
 
 2. Pass the number 50 from the right member to the left member. Then you obtain:
 
 x^2+20x+100-50=0
 x^2+20x+50=0
 
 3. Then, you must apply the quadratic equation, which is:
 
 x=(-b±√(b^2-4ac))/2a
 
 x^2+20x+50=0
 
 a=1
 b=20
 c=50
 

  4. Therefore, when you simplify, the result is:
 
  -10±5√2   (It is the last option).


 
 
 
 
 
 

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