animelunnap4kz1n animelunnap4kz1n
  • 23-02-2018
  • Mathematics
contestada

solve on the interval [0, 2pi) : 3 sec x -2 = 1

Respuesta :

carlosego
carlosego carlosego
  • 04-03-2018
First we rewrite the expression:
 3sec (x) -2 = 1
 3 (1 / cos (x)) -2 = 1
 3 (1 / cos (x)) = 1 + 2
 3 (1 / cos (x)) = 3
 (1 / cos (x)) = 3/3
 cos (x) = 1
 x = 2 * pi * n
 on the interval [0, 2pi):
 x = 0
 Answer:
 x = 0 on the interval [0, 2pi)
Answer Link
alatty
alatty alatty
  • 05-06-2020

Answer:

x = 0 on the interval [0, 2pi)

let me know if this help.

Step-by-step explanation:

Answer Link

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