21-07-2014
Mathematics

contestada

what is the vertex of the graph of the equation y= 3x^2+6x+1

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konrad509 konrad509

21-07-2014

[tex]y=a(x-h)^2+k \Rightarrow \hbox{vertex}=(h,k)\\y= 3x^2+6x+1\\ y=3x^2+6x+3-2\\ y=3(x^2+2x+1)-2\\ y=3(x+1)^2-2\Rightarrow h=-1,k=-2\\\\ (-1,-2)[/tex]

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