Respuesta :

[tex]\bf \textit{circumference of a circle}\\\\ C=2\pi r\quad \begin{cases} r=radius\\ ------\\ C=12\frac{1}{4}\pi \\\\ \qquad \frac{12\cdot 4+1}{4}\pi \\\\ \qquad \frac{49}{4}\pi \end{cases}\implies \cfrac{49\pi }{4}=2\pi r \\\\\\ \cfrac{49\underline{\pi} }{8\underline{\pi} }=r\implies \cfrac{49}{8}=r\implies 6\frac{1}{8}=r[/tex]

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