Answer is: 15675 J.
m (H₂O) = 75g - mass.
ΔT (H₂O) = 75°C - 25°C = 50°C - change in temperature.
C (H₂O) = 4,18 J/g·°C - specific heat of water.
Q = m·C·ΔT.
Q- heat (in Joules-J).
Q = 75g · 50°C · 4,18 J/g·°C = 15675J = 15,675 kJ.
Heat transfer is a discipline that study exchange, generation, use and conversion of thermal energy (heat) between physical systems.
