helenmann2016
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  • 26-11-2017
  • Mathematics
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(dH/dt)=k(68-H) find the general solution for the differential equation

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MathisLif3
MathisLif3 MathisLif3
  • 26-11-2017
dH/dt=k(68-H)
1/(68-H)dH=kt assuming k is a constant
ln|68-H|=kt+C (*)
we have all H satisfying (*)
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