pop62 pop62
  • 25-11-2017
  • Mathematics
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Graph this equation on this graph

Graph this equation on this graph class=

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hackermcpe
hackermcpe hackermcpe
  • 25-11-2017
Plot these points (0,5) (1,-1) (2,-3) (3,-1) (4,5) and then make the parabola from there
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Plasmataco
Plasmataco Plasmataco
  • 26-11-2017
Well you have that y-int=5 which is a good start

Now let's solve for the vertex form.
y=2x^2-8x+5
y-5=2x^2-8x
y-5=2(x^2-4x)
y-5+8=2(x^2-4+4)
y+3=2(x-2)^2

Thus the vertex is at (2,-3)
Now that you know this, plug in values(-1,0,1,2,3,4,5) to get (15,5,-1,-3,-1,5,15) respectively
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