In a random sample of 192 college students, 129 had part-time jobs. find the margin of error for the 95% confidence interval used to estimate the population proportion
Given data show that 129 college students out of 192 have part time jobs.
proportion p = 129/192 = 0.672
The estimated population proportion is p* = 0.672
Standard error = squareroot of [p*(1 - p*)/n] = 0.034
Value for 95% confidence interval = 1.96
margin of error = 1.96 x 0.034 = 0.067
