The solution is as follows:
Important data:
*0.01 M solution = 0.01 moles disodium ethylenediaminetetraacetate/ L solution
*1 L = 1000 mL
*Molar mass = 372/24 g/mol
Stoichiometric calculation:
0.01 mol/L * (1 L/1000 mL) * 500 mL * 372.24 g/mol = 1.8612 g
Therefore, you would need 1.8612 grams of disodium ethylenediaminetetraacetate.
