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24-08-2017
Mathematics

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find the vertex of this parabola y=-x^2+6-8

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24-08-2017

Hello,

Your equation has a mistake: it is y=-x²+6x-8.

y=-x²+6x-8
=-(x²-6x)-8
=-(x²-6x+9-9)-8
=-(x-3)²+9-8
=-(x-3)²+1

Vertex is (3,1)

An other way more speedy:
y=-x²+6x-8
y'=-2x+6 =0==>x=3 and y=-3²+6*3-8=1

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