eduarchitect
eduarchitect eduarchitect
  • 25-07-2017
  • Mathematics
contestada

can anyone help me with this:
[tex] \int\limits\, ((4x-8)/(x^{2}-4x-3)) dx
[/tex]

Respuesta :

konrad509
konrad509 konrad509
  • 25-07-2017
[tex]\displaystyle \int \dfrac{4x-8}{x^2-4x-3}\, dx=\\ 2\int \dfrac{2x-4}{x^2-4x-3}\, dx=(*)\\\\\\ \int \dfrac{f'(x)}{f(x)}=\ln(f(x))+C\\\\\\ (*)=2\ln(x^2-4x-3)+C[/tex]
Answer Link

Otras preguntas

Javier has 30 year mortgage on his 120,000 home hid bank required a 20% down payment and initially offers him a rate of 5.75% but he chose to buy 2 points and
16...06...68...88...?...98 What is the missing number??
Which of the following is a name for the place an information services and support professional might work? software development media design network adminis
What does analyzing data and graphs or charts allow you to do
Sexual reproduction
Help!! I need help, please somebody who help me
If f(x) = 6x-4, what is f(x) when x = 8
Why is Ismeme just as determined not to?
is this A B C or D???
Which conclusion could be made from Ernest Rutherford’s gold foil experiment?