How many grams of naoh would react with 507 g fecl2 in the reaction fecl2 + 2naoh fe(oh)2(s) + 2nacl?

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24-07-2017
Chemistry

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How many grams of naoh would react with 507 g fecl2 in the reaction fecl2 + 2naoh fe(oh)2(s) + 2nacl?

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Kalahira Kalahira · Answer 1 · 2017-08-02T11:11:30+02:00

Kalahira Kalahira

02-08-2017

Answer: Correct answer is 507g FeCl2 x (1 mol FeCl2 / 126.8 g FeC2) x (1 mol Fe(OH)2 / 1 mol FeCl2) x (89.8 g Fe(OH)2/ 1 mol Fe(OH)2) = 359 g Fe(OH)2.

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mmake60 mmake60 · Answer 2 · 2019-11-19T15:27:57+01:00

mmake60 mmake60

19-11-2019

Answer:320 g on apex

Explanation:

I just did it lol

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