cassistelzer67
cassistelzer67 cassistelzer67
  • 25-05-2017
  • Mathematics
contestada

please help im bad at geometry

please help im bad at geometry class=

Respuesta :

jordanmelis
jordanmelis jordanmelis
  • 25-05-2017
distance of a line=  √([x1 - x2]squared + [y1 - y2]squared)
for example, distance of JK=  √([0-5]squared + [7-5]squared)
Solving:
D= √([-5]squared + 2 squared
D=  √25+4
D= √29
D= 5.385164807 units

do this for all of the sides and add them up, that is your perimeter
Ver imagen jordanmelis
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