41 car a, moving in a straight line at a constant speed of 20. meters per second, is initially 200 meters behind car b, moving in the same straight line at a constant speed of 15 meters per second. how far must car a travel from this initial position before it catches up with car b?
according to motion 2nd equation d=vit+1/2at^2 200=20t+0 t=10 sec .... the second car let its displacement until meeting point be x d=vit+1/2 at^2 x=15t .... total displacement d=200+x ..(substituting x) d=200+15×10 =350m
