Answer:
[tex]2(9b-16)[/tex]
Step-by-step explanation:
we have
[tex]18b-32[/tex]
we know that
[tex]18=2*3^{2}[/tex]
[tex]32=2^{5}[/tex]
substitute
[tex]18b-32=2*3^{2}b-2^{5}[/tex]
Factor [tex]2[/tex]
[tex]=2(3^{2}b-2^{4})[/tex]
[tex]=2(9b-16)[/tex]
