Answer:
[tex]\huge\boxed{\sf v_f = 1.48\ m/s}[/tex]
Explanation:
Given Data:
Height = h = 9m
Acceleration due to gravity = g = 9.8 m/s²
Initial Velocity = Vi = 0 m/s
Required:
Final Velocity = Vf = ?
Formula:
[tex]2gh = v_f^2 - v_i^2[/tex] (Third equation of motion for free-falling bodies)
Solution:
2(9.8)(9) = vf² - 0²
2.18 = vf²
vf² = 2.18
Take sq. rt on both sides
vf = 1.48 m/s
[tex]\rule[225]{225}{2}[/tex]
