[tex]\mathbf{(5b+1)(2b+3)}[/tex]
1) Let's factor completely this 2nd-degree polynomial, rewriting that 17b as the sum of two terms.
[tex]\begin{gathered} 10b^2+17b+3 \\ 10b^2+15b+2b+3 \end{gathered}[/tex]
2) Now, let's group those factors and rewrite that as a product, placing outside the parentheses the GCD. Grouping the terms whose coefficient share the same
[tex]\begin{gathered} (10b^2+2b)+(15b+3) \\ 2b(5b+1)+3(5b+1) \\ \mathbf{(5b+1)(2b+3)} \end{gathered}[/tex]
Thus this is the answer (in bold).
