DhyanaK214146 DhyanaK214146
  • 25-10-2022
  • Mathematics
contestada

Find the area of the triangle described below. Round to the nearest hundredth.b = 20, a = 29, c = 21

Find the area of the triangle described below Round to the nearest hundredthb 20 a 29 c 21 class=

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KadonY387892 KadonY387892
  • 25-10-2022

Solution

We want to find the area of the triangle given te sides

b = 20

a = 29

c = 21

Note: Hero formula for calculating the Area of a Triangle

We will first find S

[tex]\begin{gathered} S=\frac{a+b+c}{2} \\ S=\frac{29+20+21}{2} \\ S=35 \end{gathered}[/tex]

To find the Area

[tex]\begin{gathered} Area=\sqrt[]{S(S-a)(S-b)(S-c)} \\ Area=\sqrt[]{35(35-29)(35-20)(35-21)} \\ Area=\sqrt[]{35\times6\times15\times14} \\ Area=\sqrt[]{44100} \\ Area=210 \end{gathered}[/tex]

Therefore, the area is

[tex]Area=210[/tex]

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