Respuesta :

we have

[tex]\frac{\sqrt[]{12x^8}}{\sqrt[]{3x^2}}=\sqrt[]{\frac{12x^8}{3x^2}=\sqrt[]{\frac{12}{3}\frac{x^8}{x^2}}}\text{ = }\sqrt[]{4x^6}=\sqrt[]{4}\sqrt[]{x^6}=2x^3[/tex]

answer:

[tex]2x^3[/tex]