Answer:
Step-by-step explanation:
The trigonometric functions are represented by the following function form:
[tex]\begin{gathered} f(x)=\text{Atrig(Bx-C)}+D \\ \text{where,} \\ A=\text{ amplitud} \\ B,C=\text{ phase shift} \\ D=\text{ vertical shift} \end{gathered}[/tex]
Then, for the following function:
[tex]f(x)=-\cot (x+\frac{\pi}{6})[/tex]
Since it is an arctan function reflected the y-axis:
