Substitute arbitrary values of x for which -10 < h(x) < 10.
In this instance, we can use x = 1, and x = -1
[tex]\begin{gathered} h(x)=-\frac{5}{8}x^5 \\ h(1)=-\frac{5}{8}(1)^5 \\ h(1)=-\frac{5}{8} \\ h(1)=-0.625 \\ \\ h(x)=-\frac{5}{8}x^{5} \\ h(-1)=-\frac{5}{8}(-1)^5 \\ h(-1)=\frac{5}{8} \\ h(-1)=0.625 \end{gathered}[/tex]
Therefore, the points that fits in the grid in the function h(x) are (1, -0.625) and (-1, 0.625).
