The potential on the surface of the charged sphere is 3.9 × 10⁷ volts.
Given:
The diameter of the sphere is 2.30 m and the charge of 1.10 mc.
The potential on the surface of a charged sphere is given by,
[tex]V=k\frac{Q}{R}[/tex]
Where V is the potential on the surface, Q is the charge, R is the radius and k is the Coulomb's constant.
V = 8.99×10⁹×5×10⁻³/(2.30÷2)
V = 3.9 × 10⁷ volts
To learn more about van de graaff generator: https://brainly.com/question/9987015
#SPJ4
