Respuesta :

LammettHash

Factorize the sum of cubes:

[tex]x^3 + y^3 = (x+y) (x^2 - xy + y^2)[/tex]

so [tex]x^2-xy+y^2[/tex] is a factor of [tex]x^3+y^3[/tex]. Then the HCF is [tex]\boxed{x^2 - xy + y^2}[/tex].

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