Given -:
change in emitter current, ∆l(E) = 4 mA
change in collector current,∆I(C) = 3.5 mA
To find -:
value of B
Solution :-
∆I(E) = ∆I(C) + ∆l(B), here ∆l(B) is the change in base current.
4 = 3.5 + ∆l(B)
∆I(B) = 0.5 mA
Now, B = ∆l (C) ÷ ∆l (B)
B = 3.5 ÷ 0.5
B = 7.0
so, the value of A = 7.0
