Respuesta :

Brainliesme

Answer:

[tex]40\pi \: {cm}^{3} [/tex] will be your answer

indrawboy

[tex]\tt V=\dfrac{1}{3}h\pi r^2\\\\V=\dfrac{1}{3}\times 10\times \pi 4^2\\\\V=\dfrac{160\pi }{3}[/tex]