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A softball field is a square with sides of length 60 feet. What is the shortest distance between first base and third base?

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A.) [tex]\sqrt{60} ft.[/tex]

B.) [tex]60 ft.[/tex]

C.) [tex]\sqrt{360} ft.[/tex]

D.) [tex]\sqrt{7200} ft.[/tex]

Please helpA softball field is a square with sides of length 60 feet What is the shortest distance between first base and third base A texsqrt60 fttexB tex60 ft class=

Respuesta :

Statement:

A softball field is a square with sides of length 60 feet.

To find out:

The shortest distance between the first base and third base, i.e., the displacement

Solution:

  • Let us consider 1st base as A, Home Plate as B and 3rd base as C.
  • AB = 60 ft
  • BC = 60 ft.
  • To find out the shortest distance between the first base and third base we have to find out the value of AC.
  • In right triangle ABC,
  • (AB)² + (BC)² = (AC)² [By Pythagoras Theorem]
  • or, (AC)² = (60 ft)² + (60 ft)²
  • or, (AC)² = 3600 ft² + 3600 ft²
  • or, (AC)² = 7200 ft²
  • or, AC = √7200 ft
  • So, the shortest distance will be √7200 ft.

Answer:

D. √7200 ft

Hope you could understand.

If you have any query, feel free to ask.

Answer:

D. 7200

Step-by-step explanation:

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