Answer:
: \large \boldsymbol {\rm x > 5 \ or \ x\in (5\ ; \ \infty ) }x>5 or x∈(5 ; ∞)
Step-by-step explanation:
\begin{gathered}\large \boldsymbol {} \displaystyle -2(3x+2) > -8x+6 \\\\ -6x-4 > -8x+6 \\\\ 8x-6x=6+4 \\\\ 2x > 10 \\\\ x > 5 \ or \ x\in (5\ ; \ \infty )\end{gathered}
−2(3x+2)>−8x+6
−6x−4>−8x+6
8x−6x=6+4
2x>10
x>5 or x∈(5 ; ∞)
