trieu0947680810 trieu0947680810
  • 22-10-2021
  • Mathematics
contestada

tập nghiệm của phương trình 3tan+√3=0

Respuesta :

sssalamry33
sssalamry33 sssalamry33
  • 22-10-2021
Tan(x) = -3/sqrt(3)
X= tan^-1(-3/sqrt(3))
X= -60 degree
Answer Link
lynnkc2000 lynnkc2000
  • 22-10-2021

Answer:

if 0° ≤ x ≤ 360°

x = 150°   or   x = 330°     (5/6 π , 11/6 π)

if x can be beyond 2π (360°) , above or below

x = 5/6 π + 2nπ      or   x = 11/6 π + 2nπ

Step-by-step explanation:

3 tanx = -√3

tan x = - 1/√3

if 0° ≤ x ≤ 360°

x = 150°   or   x = 330°     (5/6 π , 11/6 π)

if x can be beyond 2π (360°) , above or below

x = 5/6 π + 2nπ      or   x = 11/6 π + 2nπ

Answer Link

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