Richeriaa Richeriaa
  • 25-09-2021
  • Mathematics
contestada

Solve 81^x= 27^x+ ^2
Ox=1
Ox=2
Ox=5
Ox=6

Respuesta :

Happil
Happil Happil
  • 25-09-2021

Answer:

[tex]x = 6[/tex]

Step-by-step explanation:

Given:

[tex]81^x = 27^{x +2}[/tex]

Solving for [tex]x[/tex]:

[tex]81^x = 27^{x +2} \\ 81^x = (81^{\frac{3}{4}})^{x +2} \\ 81^x = 81^{\frac{3}{4}(x +2)} \\ x = \frac{3}{4}(x +2) \\ x = \frac{3}{4}x +\frac{3}{4}(2) \\ x = \frac{3}{4}x +\frac{3}{2} \\ x -\frac{3}{4}x = \frac{3}{2} \\ \frac{4}{4}x -\frac{3}{4}x = \frac{3}{2} \\ \frac{1}{4}x = \frac{3}{2} \\ x = \frac{3}{2} \cdot 4 \\ x = \frac{12}{2} \\ x = 6[/tex]

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