Step-by-step explanation:
it is given, AD=DC (S),
:. <DAB=<DCB (A) isosceles triangle,
and, <ADB=<CDB (A) BD bisector of <D.
So, by A-S-A criterion we can prove that triangle ( give it in sign) ABD = triangle ( give it in sign) CBD.
Hence, we can say that <ABD is not equal to <CDB.
Hope this helps you.
