Answer:
[tex] {x}^{2} = {(2x - 1)}^{2} \\ {x}^{2} = 4 {x}^{2} - 4x + 1 \\ 3 {x}^{2} - 4x + 1 = 0 \\ (x - 1)(x - \frac{1}{3} ) = 0 \\ \therefore \: x = 1 \: or \: x = \frac{1}{3} [/tex]
