Let's solve for x using trigonometric relation ( Cos )
we know,
[tex] \cos(30 \degree) = \dfrac{base}{hypotenuse} = \dfrac{ \sqrt{3} }{2} [/tex]
now
[tex] \dfrac{x}{8} = \dfrac{ \sqrt{3} }{2} [/tex]
[tex]x = 8 \times \dfrac{ \sqrt{3} }{2} [/tex]
[tex]x = 4 \sqrt{3} [/tex]
hence, the value of x is [tex] 4 \sqrt{3} [/tex]
