Answer:
Center (3, -8), radius = [tex]\sqrt{39}[/tex]
Step-by-step explanation:
The Standard Form for the equation of a circle is
[tex](x-h)^2+(y-k)^2=r^2[/tex]
The center is the point (h, k) and the radius is r.
Match up the given equation with the standard form.
[tex](x-h)^2=(x-3)^2 \rightarrow h=3\\(y-k)^2=(y+8)^2 \rightarrow k=-8[/tex]
That last bit can be tricky, k = -8, not 8. Watch the signs!
