Answer:
[tex] \frac{x + 7 }{x - 3} [/tex]
Step-by-step explanation:
First factorize both expressions
[tex] \frac{ {x }^{2} + 11x + 28 }{x { }^{2} + x - 12} \\ \frac{x {}^{2 } + 7x + 4x + 28 }{x { }^{2} + 4x - 3x - 12 } \\ \frac{x(x + 7) + 4(x + 7)}{x(x + 4) - 3(x + 4) } \\ \frac{(x + 7)(x + 4)}{(x + 4)(x - 3)} [/tex]
Now you can cross out x+4
and you'll be left with
[tex] \frac{x + 7}{x - 3} [/tex]
