Answer:
Third option is the correct answer
[tex] x=\pm \sqrt {26}[/tex]
Step-by-step explanation:
[tex] In (x^2 - 25)= 0[/tex]
[tex]\implies (x^2 - 25)= 10^0[/tex]
[tex]\implies x^2 - 25= 1[/tex]
[tex]\implies x^2 = 25+1[/tex]
[tex]\implies x^2 = 26[/tex]
[tex]\implies x =\pm\sqrt{ 26} [/tex]
