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21-05-2021
Biology

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What is the specific heat of aluminum if the temperature of a 28.4 g sample of aluminum is increased by 8.1oC when 207 J of heat is added? 0.900 Jg℃

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pstnonsonjoku pstnonsonjoku

23-05-2021

Answer:

0.900 Jg^-1℃^-1

Explanation:

Given that;

H = mcθ

H = heat added

m = mass of aluminium

c = specific heat of aluminum

θ = increase in temperature

Making c the subject of the formula;

c = H/mθ

c = 207 J/28.4 g * 8.1oC

c = 0.900 Jg^-1℃^-1

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