I think first you have to expand the bracket in order to get x^2+100
Then u have x^2+100-8=8
Then u have to bring 8 over the equality sign and minus it with the other -8 to get -16
It becomes x^2+100-16
Then u find the factors of 16 which add up to 100 but since that’s not possible with the formula I normally use u have to do
X=-b+&-rootb^2-4ac/2ac then simplify your answer and substitute in equation twice with plus and minus to get your answer
(I might be wrong tho)
