YanJja0smini YanJja0smini
  • 22-11-2016
  • Physics
contestada

how to solve arctan[tan(7pi /4)] ...?

Respuesta :

Аноним Аноним
  • 25-11-2016
Well, 
arctan is a bijection from R into (-pi/2 , pi/2)*and 
pi is a period of tangent function: 
so 
as we have : tan(7pi/4) = tan(pi - pi/4) = - tan(pi/4) 
we finally get : 

arctan(tan(7pi/4)) = artan(tan(- pi/4)) = - pi/4 


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