lisiMarzgum lisiMarzgum
  • 21-11-2016
  • Mathematics
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Prove the trigonometric identity:
(csc^2x)/(cotx)=cscxsecx ...?

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Nirina7
Nirina7 Nirina7
  • 22-11-2016
cscx = 1 / sinx, so csc^2x = 1/ sin²x, and cotx=cosx / sinx
so (csc^2x)/(cotx)=(1/ sin²x) (sinx/cosx) = 1/(sinxcosx) = 1/sinx  1/cosx
finally 
(csc^2x)/(cotx)=cscxsecx
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