The answer is 2) (log2)6/(log2)3.
Use the change-of-base formula: [tex]log_a(x)= \frac{log_b(x)}{log_b(a)} [/tex]
So, if we want to write log3(6) as a logarithm of base 2, in these example a = 3, x = 6, b = 2:
[tex]log_3(6)= \frac{log_2(6)}{log_2(3)}[/tex]
