since it is a first orderedlinear ODE first we look for M(t)=e^integral(2)=e^2t
then multiplying whole equation by M will give
d[(e^(2t))*y]/dt=e^(5t) * e^(2t)
d[(e^(2t))*y]=e^(7t) dt
integrating both sides gives
(e^(2t))*y=(e^(7t))/7 +C
solving the result for y gives
y= (e^(5t))/7 +C(e^(-2t)) that is the general solution of the diff. equ.
