kmahart0onCoura kmahart0onCoura

21-11-2016
Physics

contestada

If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t − 16t2. Find the velocity when t = 1.

Respuesta :

andriansp andriansp

23-11-2016

y = 42t - 16t^2

velocity = vt = dy/dt

= 42 - 32t

v(1) = 42 - 32

= 10 ft/s

Hope this helps

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