Answer:
[tex]\frac{x+4}{x+1}[/tex]
Step-by-step explanation:
Given
[tex]\frac{x^2-16}{x^2-3x-4}[/tex] ← factor numerator/ denominator
= [tex]\frac{(x-4)(x+4)}{(x-4)(x+1)}[/tex] ← cancel the factor (x - 4) on numerator/ denominator
= [tex]\frac{x+4}{x+1}[/tex]
