Answer:
for A
volume of cuboid =10×8×3=240cm³
volume of cylinder =πr²h=π×4²×7=351.85cm³
so volume of cylinder is greater
for B
surface area of cuboid =2(LB+BH+LH)=2(10×8+8×3+10×3)=268cm²
surface area of cylinder =2πr(r+h)=2×π×4(4+7)=276.36cm²
so surface area of cylinder is greater surface area than of cuboid
